Question

the eq x²-px+q=0 ,pq≤R has no real root​

Answer 1

Nature of the roots for a quadratic equation a2+bx+c=0 can be determined by its Discriminant, D=b2−4ac

 Here,         D=p2−4q

Since, the roots are not real

Therefore,

D<0

=p2−4q<0

=p2<4q

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