The eqn x^2-(p+4)x+2p+5=0 has equal roots find p
Answers
Answered by
7
Heya !!
The given equation is X² - (P + 4 )X + 2P + 5.
Here,
A = 1 , B = -(P + 4 ) and C = 2P + 5.
Discriminant ( D ) = 0
B² - 4AC = 0
(-P - 4 )² - 4 × 1 × 2P + 5 = 0
P² + 16 - 2 × -P × 4 - 4( 2P + 5 ) = 0
P² + 16 + 8P - 8P - 20 = 0
P² - 4 = 0
P² = 4
P = √4 = +2 or -2.
The given equation is X² - (P + 4 )X + 2P + 5.
Here,
A = 1 , B = -(P + 4 ) and C = 2P + 5.
Discriminant ( D ) = 0
B² - 4AC = 0
(-P - 4 )² - 4 × 1 × 2P + 5 = 0
P² + 16 - 2 × -P × 4 - 4( 2P + 5 ) = 0
P² + 16 + 8P - 8P - 20 = 0
P² - 4 = 0
P² = 4
P = √4 = +2 or -2.
Answered by
0
I hope you will be able to understand
Attachments:
Similar questions