The equal charges are separated by a distance x. Find electric field intensity in between the charge at distance x/4 from A.
Answers
Given info : Two equal charges are separated by a distance x.
To find : the electric field intensity between the charge at distance x/4 from first charge is...
solution : let magnitude of each charge is q
q ----(x/4)------(O)•-----------(x - x/4)-------------q
we have to find the electric field intensity at distance x/4 from first charge.
so, electric field at O = electric field due to 1st charge + electric field due to 2nd charge
= kq/(x/4)² (→) + kq/(3x/4)² (←)
= 16kq/x² (→) + 16kq/9x² (→)
= 16kq/x² [1 - 1/9] (→)
= 128kq/9x² (→)
Therefore the electric field intensity at O is 128kq/x² (left to right direction)
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