Math, asked by vinayraut823, 1 month ago

The equal sides of an isosceles triangle are 2cm more than its height. If the base of the triangle is 12cm, then what will be its area? (a) 24 cm² (b) 36 cm² (c) 40 cm² (d) 48 cm² Please tell the correct answer.​

Answers

Answered by apoorvakhare29
1

Answer:

ans48

Step-by-step explanation:

area = 1/2×b×h

h= √(a^2-(b^2/4))

h= √((h+2)^2-(144/4))

h=8

area=1/2×8×12

area=48

Answered by adishankar9880
0

Answer: Its 48 cm2

Step-by-step explanation:

First you have ta find x by using pythagoras theorem by taking height as x and sides as x+2 and base 12cm so x^{2} + 6^{2} =  (x+2)^{2}

then sub x and find using 1/2 base * height

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