Math, asked by seemakumarilaxmi, 5 months ago

The equal sides of the isosceles triangle are 12 cm, and the perimeter is 30cm. The area of this triangle is:

Answers

Answered by ramsanjay67261
0

Answer:

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Answered by savagekshiraj
5

ANSWER✓

Perimeter of isosceles triangle=30cm

Length of equal sides=12cm

Let third side of triangle=xcm

According to problem,

x+12+12=30

x+24=30

x=30−24

x=6

∴ Third side of triangle=6cm

Using Heron's formula

Area of triangle=

√s(s−a)(s−b)(s−c)sq. units

Where s= a+b+c/2

s= 30/2 =15

Area of triangle=

15(15−12)(15−12)(15−6)cm²

= √15×3×3×9cm²

=3×3× √15cm²

=9✓15 cm²

∴ Area of triangle=9√15 cm².

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