Question

The equatin given below has _____ real root(s)​

Answer 1

Solution :

$\large\longrightarrow\red{ \tt({x + 1)}^{2} - {x}^{2} = 0} \\ \\\large\longrightarrow\blue{ \tt{x}^{2} + x + 1 - {x}^{2} = 0}\\ \\\large\longrightarrow \green{\tt x + 1 = 0} \\ \\\large \longrightarrow \tt\orange{ x = - 1}$

Given equation has 1 real root

Answer 2

Answer:

1

Step-by-step explanation:

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