The equation 2 X square + kx + 3 is equal to zero has two equal roots then the value of K is
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2x2+Kx+3=0
a=2 , b=k & c=3
Since this equation has equal roots therefore D=0
D=b2-4ac
K2-24 =0
K2=24
K=+- root 24
K=+-2 root 6
a=2 , b=k & c=3
Since this equation has equal roots therefore D=0
D=b2-4ac
K2-24 =0
K2=24
K=+- root 24
K=+-2 root 6
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