The equation
24x2+25x−47
ax−2
=−8x−3−
53
ax−2
is true for all values of x≠
2
a
, where a is a constant.
What is the value of a?
A) -16
B) -3
C) 3
D) 16
Answers
Answered by
1
Answer:
Given,
ax−2
24x
2
+25x−47
=−8x−3−
ax−2
53
⇒
ax−2
24x
2
+25x−47
=
ax−2
(−8x−3)(ax−2)−53
⇒24x
2
+25x−47=(−8x−3)(ax−2)−53
⇒24x
2
+25x−47=−8ax
2
+16x−3ax+6−53
⇒24x
2
+25x−47=−8ax
2
+16x−3ax−47
⇒24x
2
+25x=−8ax
2
+(16−3a)x
⇒24=−8a
⇒a=−3
Answered By Roshan.
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Answered by
0
Correct option is B)
Given,
ax−2
24x
2
+25x−47
=−8x−3−
ax−2
53
⇒
ax−2
24x
2
+25x−47
=
ax−2
(−8x−3)(ax−2)−53
⇒24x
2
+25x−47=(−8x−3)(ax−2)−53
⇒24x
2
+25x−47=−8ax
2
+16x−3ax+6−53
⇒24x
2
+25x−47=−8ax
2
+16x−3ax−47
⇒24x
2
+25x=−8ax
2
+(16−3a)x
⇒24=−8a
⇒a=−3
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