Question

The equation
24x2+25x−47
ax−2
=−8x−3−
53
ax−2
is true for all values of x≠
2
a
, where a is a constant.

What is the value of a?

A) -16
B) -3
C) 3
D) 16

​

Answer 1

Answer:

You seem to have missed something from the question! I think it should read ‘… is true for all values of x, except when …’

Let’s start by multiplying both sides of the equation by (ax−2)(ax−2):

24x2+25x−47=(ax−2)(−8x−3)−5324x2+25x−47=(ax−2)(−8x−3)−53

Adding 5353 to both sides of the equation: 24x2+25x+6=(ax−2)(−8x−3)24x2+25x+6=(ax−2)(−8x−3)

Multiply out the terms in parentheses: 24x2+25x+6=−8ax2+16x−3ax+624x2+25x+6=−8ax2+16x−3ax+6

Subtracting (16x+6)(16x+6) from both sides of the equation: 24x2+9x=−8ax2−3ax24x2+9x=−8ax2−3ax

Adding 8ax2+3ax8ax2+3ax to both sides of the equation: 24x2+8ax2+9x+3ax=024x2+8ax2+9x+3ax=0

Factorising: 8(3+a)x2+3(3+a)x=08(3+a)x2+3(3+a)x=0

For this to be true for a general value of xx, we require the coefficients of x2x2 and xx to be zero ⇒a=−3

Answer is B)-3

Answer 2

Answer:

hello idoit please give unfollow i don't like any spam nonsense idoit please give me unfollow