Question

The equation
24x2+25x−47
ax−2
=−8x−3−
53
ax−2
is true for all values of x≠
2
a
, where a is a constant.

What is the value of a?

$\huge\fbox\blue{Koi He}$​

Answer 1

Answer:

Answer

Correct option is

B

−3

Given,

ax−2

24x

2

+25x−47

=−8x−3−

ax−2

53

⇒

ax−2

24x

2

+25x−47

=

ax−2

(−8x−3)(ax−2)−53

⇒24x

2

+25x−47=(−8x−3)(ax−2)−53

⇒24x

2

+25x−47=−8ax

2

+16x−3ax+6−53

⇒24x

2

+25x−47=−8ax

2

+16x−3ax−47

⇒24x

2

+25x=−8ax

2

+(16−3a)x

⇒24=−8a

⇒a=−3

Answer 2

Answer:

-3 is answer

Explanation:

Given,

ax−2

24x

2

+25x−47

=−8x−3−

ax−2

53

⇒

ax−2

24x

2

+25x−47

=

ax−2

(−8x−3)(ax−2)−53

⇒24x

2

+25x−47=(−8x−3)(ax−2)−53

⇒24x

2

+25x−47=−8ax

2

+16x−3ax+6−53

⇒24x

2

+25x−47=−8ax

2

+16x−3ax−47

⇒24x

2

+25x=−8ax

2

+(16−3a)x

⇒24=−8a

⇒a=−3