Question

The equation 24x2+25x−47ax−2=−8x−3−53ax−2 is true for all values of x≠2a, where a is a constant.

What is the value of a?

Answer 1

Given :

$24x2 + 25x - 47ax - 2 = -8x - 3 - 53ax - 2$ is true for all values of $x \neq 2a$ , where a is constant

To Find :

Value of a

Solution :

Multiply each side by ax -2

24x2 + 25x - 47ax = (-8x - 3) ( ax - 2) - 53

Solving Further

⇒ 24x2 + 25x - 47ax = -8ax2 - 3ax + 16x + 6 - 53

⇒ 24x2 + 25x - 47ax = -8ax2 - 3ax + 16x - 47

The Coefficient of both sides x2  have to equal to  on both side

-8a = 24

⇒ a = -3

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#Be  Brainly

Answer 2

Answer

multiply both sides of the given equation by ax−2. When you multiply each side by ax−2, you should have:

24x2+25x−47=(−8x−3)(ax−2)−53

You should then multiply (−8x−3) and (ax−2) using FOIL.

24x2+25x−47=−8ax2−3ax+16x+6−53

Then, reduce on the right side of the equation

24x2+25x−47=−8ax2−3ax+16x−47

Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

so answer is -3