Question

The equation 2C2H6 + 7O2 4CO2 + 6H2O if the 15 g of C2H6 react with 45 g of O2, how many grams of water will be produced?

Answer 1

Answer:

2.5 grams aprox

but I am not sure

Answer 2

Answer:

mass = 27g

Explanation:

In this type of question firstly we have to find the limiting reagent (means the reactant which is havimg less moles than the other reactant )

like for c2h6-  moles = given mass of c2h6 ÷( molar mass × stochiometric coficient)

moles of c2h6 = 15÷(30×2)

                        = 0.25

moles of o2 = 45 ÷ ( 16 ×7)

                    = 0.40

so limting reagent is c2h6

now , moles of c2h6  is equal to the moles of water

0.25= mass of water produced ÷ ( molar mass of water × stochiometric coff.)

0.25 = m ÷ ( 18 × 6)

m = 27g