Question

the equation 2x² + 3x + 1 = 0 has an irrational root​

Answer 1

Answer:

let see

b2-4ac=3square-4(1)(2)

=9-8

=1

thus b2-4ac is greater than 0 so the roots of the equation have real and distinct it means no irrational roots

the roots are -1and -1/2

Answer 2

Explanation:

To find the root of the given polynomial

We will apply The formula of

-b±√b²-4ac/2a

so

a =2

b=3

c=1

therefore

-3±√(3)²-4*2*1/2*2

=-3±√9-8 / 4

=-3±√1 /4

=-3/4

and we can convert -3/4 into decimal

i.e

-0.75

which is an irrational number

Thank you

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