Question

The equation 2x²+ kx + 3 = 0 has two equal roots , then the value of k is ±√6 ± 4 ± 3√2 ± 2√6

Answer 1

Answer:

2x^2+Kx+3

here it is in the form ax^2+bc+C=0

here a=2, b=K, c=3

if it has two equal roots. then ∆=0

b^2-4ac=0

k^2-4(2)(3)=0

k^2-24=0

k^2=24

k=√24

k=2√6

4.5

Answer 2

Answer:

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