Question

The equation 2x² + kx + 3 = 0 has two equal roots, then the value of k is​

Answer 1

Answer: k = 2√6 or -2√6

Step-by-step explanation:

we have to find the values of k for quadratic equations 2x² + kx + 3 = 0 so that they have two equal roots.

we know, quadratic equation will be equal only when

discriminant, D = b² - 4ac = 0

on comparing 2x² + kx + 3 = 0 with general form of quadratic equation , ax² + bx + c = 0 we get, a = 2, b = k and c = 3

so Discriminant , D = (k)² - 4(2)(3) = 0

or, k² - 24 = 0

or, k = ± √24 = ±2√6

hence, the value of k = 2√6 or -2√6

Answer 2

Required Answer :-

• k = ± 2√6

To find:-

• the value of k

Given quadratic equation: 2x² + kx + 3 = 0

Thus,

• Discriminant: D = b² - 4ac = 0

• Comparing 2x² + kx + 3 = 0 with the equation: ax² + bx + c = 0; we get,
• a = 2, b = k and c = 3

• Thus, D = (k)² - 4 ×(2) × (3) = 0

• => k² - 24 = 0

• k² = 24

• k = √24

• k = +2√6 or -2√6

Thus, the value of k is ± 2√6.

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