Question

the equation 3 x² - 12 X + (n- - 5) = 0 and X² + (P + 2 )X + p=0 has real and equal equal roots find the values of n and p and also find a quadratic equation whose roots are n,p​

Answer 1

Step-by-step explanation:

eq1 -.

b^2-4ac =0

144 = 12(n+5)

n= 7

eq 2

(p+2)^2= 4p

p^2+4p+4 = 4p

p^2+4=0

so p is a imaginary no.(√-4)

you can make the eq by putting values of p and n in the given eq

x^2-(p+n)X+pn

please mark BRAINIEST