Question

The equation 3r²+bx-8=0 has 2 as one of its roots. (i) What is the value of b? (ii) What is the other root of the equation?​

Answer 1

Answer:

⇒ 3x

2

+bx−8=0

Substitute x=2, since 2 is root of equation

⇒ 3(2)

2

+b(2)−8=0

⇒ 12+2p−8=0

⇒ 4+2p=0

∴ p=−2

⇒ 4x

2

−2px+k=0

⇒ 4x

2

−2(−2)x+k=0 [ Since, p=−2 ]

⇒ 4x

2

+4x+k=0

⇒ Here, a=4,b=4,c=k

⇒ It is given that roots are equal.

∴ b

2

−4ac=0

⇒ (4)

2

−4(4)(k)=0

⇒ 16−16k=0

⇒ 16k=16

∴ k=1

Step-by-step explanation:

thanks