Math, asked by prasanth60, 8 months ago

the equation 4x^2-12xy+9y^2=0 represents​

Answers

Answered by SteffiPaul
1

Therefore the given equation 4x² - 12xy + 9y² = 0 represents a 'Parabola'.

Given:

The equation: 4x² - 12xy + 9y² = 0

To Find:

The curve represented by the given equation 4x² - 12xy + 9y² = 0.

Solution:

The given question can be solved very easily as shown below.

Given equation:  4x² - 12xy + 9y² = 0

Concept:

Let us assume the given second degree equation be Ax² + Bxy + Cy² + Dx + Ey + F = 0, then the discriminant is given by B² - 4AC.

The conditions for different conics are given as follows,

⇒ For circle, B² - 4AC < 0 and B = 0 and A = C

⇒ For ellipse, B² - 4AC < 0 and B ≠ 0 and A ≠ C

⇒ For parabola, B² - 4AC = 0

⇒ For hyperbola, B² - 4AC > 0

Now comparing the given equation with the standard form.

⇒ A = 4, B = -12, and C = 9

Then B² - 4AC = (-12)² - 4(4)(9) = 144 - 144 = 0

So the discriminant B² - 4AC = 0, Hence the given equation is Parabola.

Therefore the given equation 4x² - 12xy + 9y² = 0 represents a 'Parabola'.

#SPJ2

Answered by amansharma264
1

EXPLANATION.

The equation 4x² - 12xy + 9y² = 0 represents.

As we know that,

Concepts :

A pair of straight lines through origin.

A homogeneous equation of degree two of the type ax² + 2hxy + by² = 0 always represents a pair of straight lines passing through the origin and if,

(a) h² > ab ⇒ lines are real and distinct.

(b) h² = ab ⇒ lines are coincident.

(c) h² < ab ⇒ lines are imaginary with real point of intersections that is (0,0).

Using this concepts in this question, we get.

⇒ 4x² - 12xy + 9y² = 0. - - - - - (1).

⇒ ax² + 2hxy + by² = 0. - - - - - (2).

Comparing equation (1) and equation (2), we get.

⇒ a = 4.

⇒ 2h = - 12.

⇒ h = - 6.

⇒ b = 9.

We get : a = 4,  b = 9,  h = - 6.

⇒ h² = (-6)² = 36.

⇒ h² = 36.

⇒ ab = 4 x 9 = 36.

⇒ ab = 36.

∴ h² = ab ⇒ lines are coincident.

                                                                                                               

MORE INFORMATION.

General equation of second degree representing a pair of straight lines :

ax² + 2hxy + by² + 2gx + 2fy + c = 0 represents a pair of straight lines if,

abc + 2fgh - af² - bg² - ch² = 0.

The angle θ between the two lines representing by a general equation is the same as that between the two lines representing by its homogeneous part only.

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