The equation 5x²+ (9 + 4k)x + 2k²=0 and 5 x + 9=0 are statisfied by the same value of x. find the value of k
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5x+9=0
x=(-9/5)
substitute x value in eq.
then
(81/5)+(9+4k)(-9/5)+2k^2=0
(1/5)×(81-81-36)+10k^2=0
-36+10k^2=0
-18+5k^2=0
5k^2=18
k^2=18/5
k=(+-)root (18/5)
hope it helps u
x=(-9/5)
substitute x value in eq.
then
(81/5)+(9+4k)(-9/5)+2k^2=0
(1/5)×(81-81-36)+10k^2=0
-36+10k^2=0
-18+5k^2=0
5k^2=18
k^2=18/5
k=(+-)root (18/5)
hope it helps u
jass61:
glt aa answer chaj nl krna sikhlo
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