Question

The equation ax2 + 2x +a=0 has two distinct roots, if
A.a= +1
B. a= 0
C. a=0,1
D. a= -1,0​

Answer 1

Answer:

for two distinct roots

D>0

b^2-4ac>0

so according to given equation

a=a b=2 c=a

D=b^2-4ac

=(2)^2-4*a*a

=4-4a^2

for D>0

4-4a^2>0

or

4a^2<4

a^2<1

=> a<+-1

so a<1 so a=0 or a=-1

so option D a=-1,0 is correct...