Question

The equation below shows hydrogen reacting with oxygen to produce water. 2H2 + O2 mc028-1.jpg 2H2O If 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced? 4.0 mol 8.0 mol 16 mol 32 mol

Answer 1

The reaction is 2H2 + O2 --> 2H2O
According to stoichiometry, 1 mol of O2 will react with 2 mol of H2. Hence 16 mol of O2 will react with 32 mol of H2.
So the ans. is 32

Answer 2

Answer: 32 moles of water will be produced.

Explanation: For the given reaction:

$2H_2(g)+O_2(g)\rightarrow 2H_2O(l)$

Here, the hydrogen gas is present in excess, so it is considered as excess reagent. Oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry,

1 mole of Oxygen produces 2 moles of water, then

16 moles of oxygen will produce = $\frac{2}{1}\times 16=32moles$

Therefore, 32 moles of water will be produced.