Question

the equation by increased each roots 2x^2-3x-1=0 by 2 is​

Answer 1

Answer:

2x^2-5x+3=0

Step-by-step explanation:

Initial equation: 2x^2-3x-1=0

Roots by solving it are: -1 & -1/2

Roots of new equation by increasing each by 2: -1+2=1 & -1/2+2=3/2

By having the roots we can put as:

(x-1)(2x-3)=0 =>2x^2-3x-2x+3=0

And get new equation:

2x^2-5x+3=0

Hope it helps

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