The equation esinx – e-sinx – 4 = 0 has
Infinite number of real roots
No real roots
Exactly one real root
Exactly four real roots
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Step-by-step explanation:
equation esinx-e-sinx-4=0 has (A) infinite number of real roots (B) no real roots (C) exactly one real root (D) exactly four real roots. JEE main paper will be in multilingual and preference will be given to states with maximum number of applications.
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Answer:
The correct option is B.
Step-by-step explanation:
esinx – e-sinx – 4 = 0
t = esinx
t – 1/t = 4
t2 – 4t – 1 = 0
t = 4 ± √16 + 4 / (2)
t = 4 ± 2√5 / (2)
t = 2 ± √5
esinx = 2 ± √5
-1 ≤ sinx ≤ 1
1/e ≤ esinx ≤ e
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