Math, asked by MohanChod11, 8 months ago

The equation esinx – e-sinx – 4 = 0 has

Infinite number of real roots
No real roots
Exactly one real root
Exactly four real roots

Answers

Answered by Anonymous
0

Step-by-step explanation:

equation esinx-e-sinx-4=0 has (A) infinite number of real roots (B) no real roots (C) exactly one real root (D) exactly four real roots. JEE main paper will be in multilingual and preference will be given to states with maximum number of applications.

Answered by Anonymous
1

Answer:

The correct option is B.

Step-by-step explanation:

esinx – e-sinx – 4 = 0

t = esinx

t – 1/t = 4

t2 – 4t – 1 = 0

t = 4 ± √16 + 4 / (2)

t = 4 ± 2√5 / (2)

t = 2 ± √5

esinx = 2 ± √5

-1 ≤ sinx ≤ 1

1/e ≤ esinx ≤ e

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