Question

the equation for a hyperbola is shown

x^2/25 - y^2/49=1

what are the lengths of the transverse and conjugate axes?

Answer 1

Answer:

The equation 16x^2 - 9y^2 = 144. can be written as x^2/9 - y^2/16 = - 1 This is of the form x^2/a^2 - y^2/b^2 - 1 a^2 = 9,b^2 = 16 a = 3,b = 4 Length