Question

The equation for line c can be written as
y = –1/9x − 5. Line
d includes the point(–6, 3)and is parallel to line
c. What
is the equation of line
d?

Answer 1

Answer:

I hope it will help you

Step-by-step explanation:

Solution,

here,

Given equation c is

y = –1/9x − 5

or, 1/9x + y = − 5.

(m1) slope of equation c = -x/y

= -1/9/1 = -1/9

Since equation d is parallel to c

so, m1 = m 2

i.e. Slope equation d=slope of equation c

we know

Equation of the line d having slope = m2 = -1/9

passing though the point (-6, 3) is

y - y1 = m ( x - x1)

or, y - 3 = -1/9 (x + 6)

or, 9 y - 27 = -x - 6

or, x + 9y = - 6 + 27

or, x + 9y + 21 = 0

therefore,

.x + 9y + 21 = 0 is the equation of d.