Question

the equation for line j can be written as y=2x+8. another line k is perpendicular to line j and passes through the (6,-6). choose the equation for like k

A) y=2/1 x-3
B) y= -1/2x - 3
C) y=-2x-3
B) y=-3/2x+3



line m has a slope of -3. another line n is parallel to line m. what is the slope of line n?

Answer 1

Answer:

The equation for line j can be written as y=x+85. Line k includes the point(-10, 2)and is perpendicular to line j. What is the equation of line

The equation for line j can be written as y=x+85. Line k includes the point(-10, 2)and is perpendicular to line j. What

is the equation of line? the answer has to be in slope intercept form

mark as brainliest ans

Answer 2

equation of line k is y = (-2x) + 8 .

Step-by-step explanation:

Given,equation of line j is Y=2x+8

It is of the form Y = mx + c

here m is called slope

also given k is perpendicular to j

so slope of j is (-2) ; Since slope of line a and b which are mutually perpendicular if slope of one line is m then the other is (-m).

Therefore equation of line k is y = (-2)x+8

》》slope of 'n' is zero (0)

● since slope of line a parallel to a line b is zero . since there is no angle between them.

slope = m = tan a where a is any angle