Question

The equation for the action of heat on calcium nitrate is:

2Ca(NO3)2 2CaO + 4 NO2 + O2

(i) How many moles of NO2 are produced when 1 mole of Ca(NO3)2 decomposes?

(ii) What volume of O2 at S.T.P. will be produced on heating 65.6 g of Ca (NO3)2?

(iii) Find out the mass of CaO formed when 65.6 g of Ca(NO3)2 is heated.

(iv) Find out the mass of Ca(NO3)2, required to produce 5 moles of gaseous

products.

(v) Find out the mass of Ca(NO3)2 required to produce 44. 8 L of NO2 at S.T.P.

(Relative molecular mass of Ca(NO3)2 = 164 and of CaO = 56)

Answer 1

When potassium nitrate is heated it produces potassium oxide ,nitrogen gas alongwith oxygen as by products

4KNO3(s)———→2K2O(s)+2N2(g)+5O2(