Question

the equation for the reaction of magnesium with water is MG + 2H2O give mg(oh)2 with water
how many moles of MgOH2 is produced when magnesium reacts with water

what volume of H2 at ntp will be produced on the acting 48 G of magnesium with 22 gram of water ​

Answer 1

Answer:

Solution:- (C) 30

As we know that,

No. of moles=

mol. wt.

wt.

Now,

Wt. of Mg=6g

Mol. wt. of Mg=24g

No. of moles of Mg in 6g=

24

6

=0.25 moles

Mg+H

2

SO

4

⟶MgSO

4

+H

2

from the above reaction,

1 mole of magnesium sulphate is formed when 1 mole of magnesium reacts.

Therefore,

0.25 mole of magnesium sulphate is formed when 0.25 mole of magnesium reacts.

Now,

Mol. wt. of MgSO

4

=120g

Therefore,

Wt. of 0.25 moles of MgSO

4

=0.25×120=30g

Hence 30g of magnesium sulphate is formd when 6g of magnesium reacts with excess of H

2

SO

4

.