The equation for the statement " The sum of the numbers x and twice the number y is 12 " can be expressed as
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Solution :
(i) The sum of three times x and 11 is 32. →3x+11=32→3x+11=32
(ii) If you subtract 5 from 6 times a number, you get 7. →6x−5=7→6x-5=7
(iii) One fourth of m is 3 more than 7.→14m−7=3→14m-7=3
(iv) One third of a number plus 5 is 8.→13x+5=8
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