the equation (k-1)x+(3k+1)y+2kz=0, (k-1)x+(4k-2)y+(k+3)z=0, 2x+(3k+1)y+3(k-1)z=0. gives non-trivil solutions for some values of k then the ratio x:y:z when k has the smallest of these values. (a) 3:2:1. (2) 3:3:2 (3) 1:3:1 (d) 1:1:1
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2- 1:3:1 is the answer of this question.
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