Question

.The equation (k + 4) x² + (k + 1) x + 1 = 0 has equal roots. (i) How many values exist for k?
(ii) the whole no value of k?
(iii) the roots of equation are
(iv) the discriminant of equation is?

plz someone ans all the parts with explanation..tomorrow is my board exam so plz help!!​

Answer 1

Answer:

(k+4)x2+(k+1)x+1=0. Since the given quadratic equation has equal roots, its discriminant should be zero. Thus, the values of k are 5 and −3. Thus, the equal root of the given quadratic equation is either 1 or −13.

Answer 2

Step-by-step explanation:

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