Question

The equation {[(l-m)/2]x^2} - {[(l+m)/2}x] + m=0 has got 2 values of x to satisfy the equation given as​

Answer 1

Answer:

given below

Step-by-step explanation:

m−n)x

2

+(n−l)x+l−m=0

It has equal roots hence

Δ=0

(n−l)

2

−4(e−m)(m−n)=0

n

2

+l

2

−2ln−4(lm−m

2

−ln+mn)=0

n

2

+l

2

−2ln−4lm+4m

2

+4ln−4mn=0

n

2

+l

2

+2ln+4m

2

−4lm−4mn=0

(n+l−2m)

2

=0

n+l=2m

Answer 2

Step-by-step explanation:

ंthis is a answer

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