Question

The equation log x to base e + log 1+x to base e =0 can be written as

Answer 1

Answer:

log x to base e + log 1+x to base e =0

log x ( 1 +x ) to base e =0

 e^0 = x ( 1 +x )

1 =x ( 1 +x )

1 = x + x²

x² + x -1 =0   ( answer )