The equation log x2 +6x+8)log
(2x² + 2x+3)(x² – 2x)=Ohas
(B) Exactly one solution
(A) Exactly two solutions
(C) Sum of all the solutions is – 4
(D) Sum of all the solutions - 1
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2x2x2+2x2(−2x)+2x⋅x2+2x(−2x)+3x2+3(−2x)2x2x2+2x2(-2x)+2x⋅x2+2x(-2x)+3x2+3(-2x)
2x4−2x3−x2−6x2x4-2x3-x2-6
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