Question

The equation logex+loge(1+x)=0 can be written as

Answer 1

Answer:

Step-by-step explanation:

x2 + x – 1 = 0... ................

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Answer 2

Answer:

$log_{e}(x) + log_{e}(1 + x) = 0 \\ log_{e}( {x}^{2} + x ) = 0 \\ {x}^{2} + x = 1 \\ {x}^{2} + x - 1 = 0$

Step-by-step explanation:

if you want the values of X,then,

$x = \frac{ - 1 - \sqrt{5} }{2} \: or \: x = \frac{ - 1 + \sqrt{5} }{2}$

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