Question

The equation of a circle is x^2+y^2-8x+4y+4=0
a) Find the radius of the circle and the coordinates of its center.
b) Find the x-coordinates of the points where the circle crosses the x-axis, giving your answer in exact form.
c) Show that the point A(6, 2√3-2) lies on the circle.
d) Show that the equation of the tangent to the circle at A is √3x+3y=12√3-6.

Answer 1

1184472,+184(4827+376_27