The equation of a circle is x2 + y2 + Cx + Dy + E = 0. If the radius of the circle is decreased without changing the coordinates of the center point, how are the coefficients C, D, and E affected?
A.
C, D, and E are unchanged.
B.
C increases, but D and E are unchanged.
C.
C and D decrease, but E is unchanged.
D.
C, D, and E increase.
E.
C and D are unchanged, but E increases.
Answers
Answered by
15
Given,
The equation of a circle is x2 + y2 + Cx + Dy + E = 0
The radius of the circle is decreased without changing the coordinates of the center point.
As we know that, the general equation of the circle is given by,
x^2 + y^2 + 2gx +2fy +c = 0
Comparing the given equation with the standard equation of a circle, we get,
C = 2g and D = 2f
as the coordinates of the center of the circle is (-g, -f) which remains unchanged
. So, we get, C and D are unchanged.
But we know that the radius of a circle is given by r = √(g^2 + f^2 - c)
Here c is E and we are given that radius is decreased which is only possible when the value of c i.e. E gets increased.
Therefore, we have, C and D are unchanged, but E increases.
Option E is correct.
Similar questions