Question

The equation of a circle which passes through the three points (3, 0) (1,-6), (4, -1) is -
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Answer 1

Explanation:

Equation of circle in general form is x² + y² + 2gx + 2fy + c = 0 and in radius form is (x – h)² + (y -k)² = r², where (h, k) is the center of the circle and r is the radius. The equation of the circle is x2 + y2 = 1.

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Answer 2

Answer:

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