Question

The equation of a circle with origin as centre
and passing through the vertices of an
equilateral triangle whose median is of
length 3a is
(A)r + y2 =9a (B) x + y2 = 1622
(Cr+ y = 4a² (D) x + y2 = a?​

Answer 1

Answer:

(d) x+y2=a is the equation of the circle

Answer 2

Answer:

C) x^2 + y^2 = 4a^2

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