Question

the equation of a circleof radius 3is x2 +y2 +10x-8y+k=0 find the value of the constant k

Answer 1

Given equation of circle is

x² + y² + 10x - 8y + k = 0

Here, g = 5 & f = -4

So, centre, C(-g, -f) = C(-5, 4)

And, radius, r = 3

So, r = √(g² + f² - k)

→ 3 = √((-5)² + 4² - k)

Squaring both sides

→ 9 = 25 + 16 - k

→ k = 41 - 9

→ k = 32 __________________(Ans.)

Answer 2

Answer:

Step-by-step explanation: