the equation of a curve is given as y=x^2+2-3x. the curve intersects the y axis at
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Answer:
If the equation of a curve is given as y=x^2+2-3x and the curve intersects the y axis
Then x= 0
Which gives
y = 2
So the required point is (0,2)
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Explanation:
a curve y= f(x) intersects y axis at y= f(0)
therefore here f(0) = 2.
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