Question

The equation of a line 3x + 4y - 7 = 0 find (1) slope of line
(ii) Equation of line perpendicular to given line and passing through
the intersection of line x - y + 2 = 0 and 3x + y - 10 = 0​

Answer 1

Answer:

See this attachment

This is the best possible answer

Hope you have understood

$<marquee>⭐Please mark it as⭐</marquee>$

$\huge\underline\mathcal\red{Brainliest}$

$</p><p>\huge{\boxed{\mathbb\green{\fcolorbox{red}{blue}{Thank\:You}}}}$

Answer 2

Answer:

3x + 4y – 7 = 0 .....(1)

1) Slope of the line m =

coefficient of x

coefficient of y

=

−

3

4

coefficient of xcoefficient of y=-34

2) Equation of line perpendicular to the given line

4x – 3y = λ ......(2)

Solving the equations x – y + 2 = 0 and 3x + y – 10 = 0, point of intersection is (2, 4).

Line (2) passes through points (2, 4).

4(2) – 3(4) = λ ⇒ λ = –4

Hence, the equation of required line is

4x - 3y + 4 = 0

plz mark me as brainliest!!!!

Step-by-step explanation: