Question

the equation of a line parallel to 3x-2y+5=0 and passes through the point (5,-6) is ax+by+c=0 then a+b+c=​

Answer 1

Answer:

HEY MATE!

Here is your answer:

3x-2y+5=0 ___(1)

Put the value of x and y in eq (1)

3(5)-2(-6)+5=0

Here, a = 3

b = (-2)

c = 5

according to the question,

a+b+c = 3+(-2)+5

= 3-2+5

=1+5 = 6

HOPE IT HELPS

Answer 2

The equation of a line parallel to $3x-2y+5= 0$ and passes through the point (5,-6) is $ax+by+c=0$  then a+b+c = -15.

Explanation:

Given:

x = 5, y = -6

Parallel lines = 3x - 2y + 5 ⇔ ax + by + c------- (1)

Point slope parallel line equation = y - y₁ = 2(x - x₁)

substituting the values, y + 6 = 2(x - 5)

y + 6 = 2x - 10

2x - y - 16 = 0 ---------(2)

Solving both the equations:

we get a(5) +b(-6) + c = 2(5) +6 - 16 = 0

5a - 6b + c = 10 + 6 - 16

a = 2, b = -1, c = - 16

Therefore,

a + b + c = 2 - 1 - 16 ⇒ - 15

a + b + c = - 15.

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