the equation of a line parallel to x axis and at a distance 3 units below it is
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Answer:
x+2y−3=0........................(i)
2x−y+5=0.......................(ii)
1× (i)+2× (ii), we get
⇒5x+7=0
⇒x=
5
−7
putting value of x in (i), we get
5
−7
+2y−3=0⇒y=
5
11
x=
5
−7
,y=
5
11
and slope of y−x+10=0⇒y=(x−10) is =1
Therefore, Equation of the line will be,
(y−
5
11
)=(x−
5
−7
)⇒5y−11=5x+7⇒5x−5y+18=0
Step-by-step explanation:
hope it helps you
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-- :
Any straight line parallel to x−axis is given by y=k, where k is the distance of the line from x−axis. Here k=−3, because it is below x axis then the equation of the line is y=−3.
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