the equation of a line passing through (-1,-1) and perpendicular line whose slope is -2/5
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Hi!!!!
The equation of a line is given as
(y-y1)=m(x-x1)
where; (x1,y1) is the point on the line and m is the slope
As the line is perpendicular to the line whose slope is -2/5
m1*m2= -1
m1*(-2/5)= -1
m1= 5/2
Now, substitute the values in the equation
(y-(-1))=5/2(x-(-1))
y+1=5/2(x+1)
2y+2=5x+5
5x-2y+5-2=0
5x-2y+3=0
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