Question

the equation of a line passing through (4,-2) and (-1,3) is​

Answer 1

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In (4,-2) and (-1,3) ,

• x₁ = 4.
• y₁ = -2.
• x₂ = -1
• y₂ = 3

First, you find the gradient of the line using the formula :

$\to \sf m=\dfrac{(y_2-y_1)}{(x_2-x_1)}$

Substitute.

$\to \sf m=\dfrac{(3-(-2))}{(-1-4)}$

$\to \sf m=-1$

Now use the formula:

$\to \sf (y-y_1) = m(x-x_1)$

Where x and y are variables.

$\to \sf (y-(-2)) = -1(x-4)$

$\to \sf y+2= -x+4$

$\to \sf x+y= 2$

Proof: See the file attached.