Question

the equation of a line passing through (-4,3,1) parallel to the plane x+2y-z-5=0 and interesting line x+1/-3=y-3/2=z-2/-1 is​

Answer 1

Answer:

Correct option (4) x + 4/3 = y- 3/-1 = z - 1/1 Explanation: Let P.O.I. of line is (–3λ – 1, 2λ + 3, – λ + 2) Direction cosines of line is (–3λ + 3, 2λ, –λ + 1). Since this line is parallel to x + 2y – z = 5 hence dot product is zero. (–3λ + 3)1 + 4λ –1(– λ + 1) = 0 λ = –1 Hence direction cosines 6, –2, 2 are x + 4/3 = y- 3/-1 = z - 1/1Read more on Sarthaks.com - https://www.sarthaks.com/331097/the-equation-of-the-line-passing-through-4-3-1-parallel-to-the-plane-x-2y-z-5-0?show=331105#a331105