The equation of a line passing through a point (4, 5) and having slope units is 3 2. O 3X – 24 - 2 = 0 - 3x - 2y + 22 = 0 O 3x + 2y + 2 = 0 3x + 2y + 17 =0
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Step-by-step explanation:
Let the Slope of line be m
Now, slope of other lines are 43,512
The Slope is Equally inclined so it must lie between these slopes
such that
43<m<512
As it is equally inclined so angle between the line and the two given line must be same
⇒θ1=θ2⇒tanθ1=tanθ2⇒1+512m512−m=1+43mm−43⇒63m2−32m−63=0
⇒m=2∗6332±322+4∗63∗63⇒m=9−7,79
Now, Equation of line as it passes through (4,5) will be
y−5=m(x−4)
Putting the obtained values of m in above Equation we get
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