Question

The equation of a line passing through the origin and perpendicular to the line 7x-3y+4=0 is

Answer 1

SOLUTION

TO DETERMINE

The equation of a line passing through the origin and perpendicular to the line 7x - 3y + 4 = 0

CONCEPT TO BE IMPLEMENTED

The equation of the line perpendicular to the line ax + by + c = 0 is bx - ay + k = 0

Where k is a constant to be determined

EVALUATION

Here the given equation of the line is

$\sf{7x - 3y + 4 = 0 \: } \: \: \: .....(1)$

Since the required equation of the line is perpendicular to the line given by Equation (1)

So the required equation of the line is of the form

$\sf{ 3x + 7y + c = 0\: } \: \: ....(2)$

Now the line given by the equation (2) passes through origin (0,0)

So

$\sf{ (3 \times 0) + (7 \times 0 )+ c = 0\: }$

$\implies \sf{ c = 0\: }$

Hence the required equation of the line is

$\sf{ 3x + 7y = 0\: } \: \:$

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LEARN MORE FROM BRAINLY

Draw the graph of the linear equation 3x + 4y = 6.

At what points, the graph cuts X and Y-axis?

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