The equation of a line passing through the origin and perpendicular to the lime 7x+7y=0 is _______ a) 7x-3y+4=0 b)3x-7+4=0 c) 3x+7y=0 d)7x-3y=0
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Let the slope of the unknown line be m.
Slope of line AB =−
3
7
Slope of line AC =−
7
3
∠ABC=
3−7m
−7−3m
∠ACB=
7−3m
−3−7m
As the sides are equal, so should the angles.
3−7m
−7−3m
=
7−3m
−3−7m
49−9m
2
=9−49m
2
40m
2
=−40
m=∓1
Hence, the equation of the line is
y−3=−(x+3)
y+x−6=0
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